2(y)^1/2+2=5*(y)^1/4

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Solution for 2(y)^1/2+2=5*(y)^1/4 equation: 


y in (-oo:+oo)

(2*y^1)/2+2 = (5*y^1)/4 // - (5*y^1)/4

(2*y^1)/2-((5*y^1)/4)+2 = 0

(2*y)/2+(-5/4)*y+2 = 0

2-1/4*y = 0 // - 2

-1/4*y = -2 // : -1/4

y = -2/(-1/4)

y = 8

y = 8

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